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A particle P is projected Vertically upward from a point A . Six seconds later, another particle Q is projected vertically upward from A . Both P and Q reach A simultaneously. The ratio o f maximum heights reached by P and Q=65 : 25. Find thevelocity of the projection of Q in m//s. |
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Answer» SOLUTION :`1/2 G(t+3)^(2), 1/2 "GT"^(2) =64:25 `(or) `(t+3)^(2):t^(2)=64:25,`(or)`(t+3):t=8:5` `5t+15=8t`(or)`3t=15,t=5sec` `v=gxxt = 9.8xx5=49m//s=5g m//s` |
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