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A particle performing circular motion with its diameter d and velocity v. Then the angular displacement of the particle in time t isA. `(vt)/(d)`B. `(2vt)/(d)`C. `(vt)/(2d)`D. `(d)/(vt)` |
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Answer» Correct Answer - B `theta= omegat` `=(V)/(r)t=(2V)/(2r)t` `theta=(2Vt)/(d)`. |
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