A particle performing linear S.H.M. has a maximum displacement of 0.1 m. Its acceleration at a distance of 0.03 m from its position is 0.12 m//s^2. What is its velocity at a distance of 0.06 m from its mean position ?

A particle performing linear S.H.M. has a maximum displacement of 0.1

1.	A particle performing linear S.H.M. has a maximum displacement of 0.1 m. Its acceleration at a distance of 0.03 m from its position is 0.12 m//s^2. What is its velocity at a distance of 0.06 m from its mean position ?
Answer» SOLUTION :`v=omegasqrt(a^2-x^2) = SQRT(AC c^n/x)xsqrt(a^2-x^2)` `sqrt0.12/0.13xxsqrt((0.1)^2-(0.06)^2)` `2sqrt(0.01-0.0036)` `2sqrt0.0064=2xx0.08=0.16m/s.`

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A particle performing linear S.H.M. has a maximum displacement of 0.1 m. Its acceleration at a distance of 0.03 m from its position is 0.12 m//s^2. What is its velocity at a distance of 0.06 m from its mean position ?

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