A particle performs a SHM with amplitude of 0.01m and the frequency of its oscillation is 60 Hz. Find the maximum acceleration of a particle.

A particle performs a SHM with amplitude of 0.01m and the frequency of

1.	A particle performs a SHM with amplitude of 0.01m and the frequency of its oscillation is 60 Hz. Find the maximum acceleration of a particle.
Answer» `144 pi^(2) m"/"sec^(2)` `144M"/"sec^(2)` `(144)/(pi^2) m"/"sec^(2)` `288 pi^(2) m"/"sec^(2)` Solution :MAXIMUM acceleration `= A OMEGA^(2)` `= A xx 4pi^(2) F^(2)` `=0.01xx 4 (pi)^(2)xx (60)^(2)` `= 144 pi^(2) m"/"s^(2)`.