A particle performs simple harmonic motion with speed v and acceleration a. Which of following statement is true ?

A particle performs simple harmonic motion with speed v and accelerati

1.	A particle performs simple harmonic motion with speed v and acceleration a. Which of following statement is true ?
Answer» Velocity is MAXIMUM, WHEREAS acceleration is zero. When velocity is maximum, its acceleration is maximum For any value of v, the value of a is zero When v is zero, a is also zero. Solution :Particle of SHM have maximum velocity at mean POSITION. So in `v= pm OMEGA sqrt(A^(2)-x^(2)), x=0` `THEREFORE v= A omega` is maximum value of velocity and in acceleration `a= -omega^(2)x, x=0, a=0`.