A particle performs uniform circular motion with an angular momentum L . If the frequency of particle's motion is doubled and its kinetic energy is halved , then find the new angular momentum in terms of L.

A particle performs uniform circular motion with an angular momentum L

1.	A particle performs uniform circular motion with an angular momentum L . If the frequency of particle's motion is doubled and its kinetic energy is halved , then find the new angular momentum in terms of L.
Answer» SOLUTION :`E_(k) = (1)/(2) I OMEGA^(2) = (1)/(2) (I omega) (2 PI epsilon)` `E_(k) = pi epsilon L implies L = (E_(k))/(pi * epsilon)` If `epsilon` is DOUBLED and `E_(k)` is halved , then `L. = ((E_(k) //2))/(pi (2epsilon)) = (1)/(4) ((E_(k))/(pi epsilon))= (L)/(4)`