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A particle projected at angle 60^(@)with speed 10sqrt(3),from the point 'A' as shown in the figure. At the same time the wedge is made to move with speed10sqrt(3) towards right as shown in the figure. |
Answer» <html><body><p>time taken by <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> to strike <a href="https://interviewquestions.tuteehub.com/tag/wedge-1451188" style="font-weight:bold;" target="_blank" title="Click to know more about WEDGE">WEDGE</a> is <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> sec<br/>Range on wedge is <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> m<br/>Maximum horizontal displacement `10sqrt(3)m`<br/>Final velocity of particle is 10 m/s</p>Answer :A::B::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>::D</body></html> | |