A particle projected horizontally from P, so that it hits the inclined plane perpendicularly Time of journey is

A particle projected horizontally from P, so that it hits the inclined

1.	A particle projected horizontally from P, so that it hits the inclined plane perpendicularly Time of journey is
Answer» `SQRT((2H COS^(2)theta)/(g(1+SIN^(2)theta)))` `sqrt((2h sin^(2) theta)/(g(1+sin^(2)theta)))` `sqrt((2hcos^(2) theta)/(g(1+cos^(2) theta)))` `sqrt((2h)/(g cos theta))` Answer :A