A particle slides down from rest on an inclined planet of angle theta with horizontal and the distances are as shown. The particle slides down from top to the position A, where it's velocity is v. Then below correct options are

A particle slides down from rest on an inclined planet of angle theta

1.	A particle slides down from rest on an inclined planet of angle theta with horizontal and the distances are as shown. The particle slides down from top to the position A, where it's velocity is v. Then below correct options are
Answer» `(V^(2)-2gH)` will remain constant `(V^(2)-2gSsin THETA)` will remain constant `[V^(2)-2gS[H-h)/(p-s)]` will remain constant `[V^(2)-(2gSH)/p]` will remain constant Answer :A::B::C::D