Saved Bookmarks
| 1. |
A particle starting from rest moves in a straight line with acceleration asshown in the a-t graph. Find the distance (in m) travelled by the particle inthe first four seconds from start of its motion. |
|
Answer» Answer: ✔Initial velocity of the particle(u) = 0 ✔Final velocity of the particle, V = 18 km/h = 5m/s ▶Time(t) = 5s ▶Acceleration(a) = (v − u)/t ▶a = (5 − 0)/5 = 1 m/s^2 ▶DISTANCE (s) =ut+1/2at^2 ▶s=12×1×(5×5)=12.5 m a) Average velocity =Total displacement/Total time taken ▶Average =(12.5)/5 = 2.5 m/s b) Distance travelled, s = 12.5 m |
|