1.

A particle starting from rest moves in a straight line with acceleration asshown in the a-t graph. Find the distance (in m) travelled by the particle inthe first four seconds from start of its motion.​

Answer»

Answer:

✔Initial velocity of the particle(u) = 0

✔Final velocity of the particle, V = 18 km/h = 5m/s

▶Time(t)  = 5s

▶Acceleration(a) = (v − u)/t

▶a = (5 − 0)/5 = 1 m/s^2

DISTANCE (s) =ut+1/2at^2

▶s=12×1×(5×5)=12.5 m

a) Average velocity =Total displacement/Total time taken

▶Average =(12.5)/5 = 2.5 m/s

b) Distance travelled, s = 12.5 m



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