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A particle starts from rest and travels a distance 's' with uniform acceleration, then it travels a distance '2s' with uniform speed and finally it travels a distance '38' with uniform retardation and comes to rest. If whole motion is in a straight line, the ratio of maximum velocity to average velocity is |
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Answer» Solution :Here s= area of v-t graph LET v be MAXIMUM velocity, then `s=(1)/(2) ut_(1)` `:. t_1=(2S)/(v)` Also `2s=vxxt_(2)` `t_2=(2s)/(v)` and`3s=(1)/(2)vt_(3)` `t_(3)=(6s)/(v)` Then `v_(av)=(6s)/((2s)/(v)+(2s)/(v)+(6s)/(v))=(6sxxv)/(10 s)=(3)/(5)v` Now `v_(max)=v` `:. (v_(max))/(v_(av))=(v)/(3//5v)=(5)/(3)`
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