A particle starts from rest with a time varying acceleration a=(2t−4). Here t is in s and a in m/s2. At what time, particle will have maximum velocity in negative direction?

A particle starts from rest with a time varying acceleration a=(2t−4

1.	A particle starts from rest with a time varying acceleration a=(2t−4). Here t is in s and a in m/s2. At what time, particle will have maximum velocity in negative direction?
Answer» A particle starts from rest with a time varying acceleration $a = (2 t - 4)$ . Here $t$ is in $s$ and $a$ in $m / s^{2}$ . At what time, particle will have maximum velocity in negative direction?

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A particle starts from rest with a time varying acceleration a=(2t−4). Here t is in s and a in m/s2. At what time, particle will have maximum velocity in negative direction?

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