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A particle starts from rest with constant acceleration. The ratio of space-average velocity to the time average velocity is :-A. `1//2`B. `3//4`C. `4//3`D. `3//2`

Answer» Correct Answer - C
`lt v_("space") gt =(int" vds")/(int" ds")=(int sqrt(2as)ds)/(int ds)=2/3 v`
`lt v_("time") gt =(int" vdt")/(int" dt")=(int" atdt")/(int" dt")=v/2 :. (lt v_(s) gt)/(lt v_(t) gt)=4:3`


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