Saved Bookmarks
| 1. |
A particle starts its motion from rest under the action of a constant force. If the distance covered in first `10 s` is `s_1` and the covered in the first `20 s` is `s_2`, then.A. `s_(2)=2s_(1)`B. `s_(2)=3s_(1)`C. `s_(2)=4s_(1)`D. `s_(2)=s_(1)` |
|
Answer» Correct Answer - C A particle ……….. If the particle is moving in a straight line under the action of a constant force then distance covered `s=ut+(1)/(2)at^(2)` Since the body starts from rest `u = 0` `:. s = (1)/(2)at^(2)` Now, `s_(1)= (1)/(2)a(10)^(2)` ............(i) and, `s_(2)= (1)/(2)a(20)^(2)` .............. (ii) Deividing Eq (i) and Eq (ii) we get `(s_(1))/(s_(2)) = ((10)^(2))/((20)^(2))` `implies s_(2) = 4s_(1)` |
|