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A particle starts with an initial velocity `2.5 m//s` along the posiive x-direction and it accelerates uniformly at the rate `0.50 m//s^2.` (a) Find the distance travelled by it in the first two seconds (b) How much time does it take to reach the velocity `7.5 m//s` ? (c) How much distance will it cover in reaching the velocity `7.5 m//s`? |
Answer» Correct Answer - A::B::C (a) `S=ut+1/2 at^2` `=(2.5xx2)+1/2(0.5)(2)^2` `=6m=distance also` (b) `v=u+at` `7.5=2.5+0.5xxt rArr t=10s` (c) `v^2=u^2+2as` `:. (7.5)^2=(2.5)^2+(2)(0.5)s` `rArr s=50 cm`=distance also |
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