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A particle starts with constant angular acceleration of `"2 rad/s"^(2)` in a circle of radius 4m. Find angle between net acceleration and radial acceleration after 2 s :-A. `theta=tan^(-1)((1)/(8))`B. `theta=tan^(-1)((1)/(4))`C. `theta=tan^(-1)((1)/(2))`D. `theta=tan^(-1)((1)/(16))` |
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Answer» Correct Answer - A `vec(alpha)=2"rad/s"` `r=4m` `omega=0+2(2) rArr omega=4"rad/s"` `a_("cp")=omega^(2)r=64` `a_(t)=alphar=8` `tan alpha=((a_(t))/(a_(r))), alpha=tan^(-1)((1)/(8))` |
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