1.

A particle travels from point A to B on a circular path of radius 15//picm . If the arc length AB be 10 cm , find the displacement (Figure)

Answer»

Solution :Joining the initial (A) and final (B) positions of the body, the straight line AB is obtained which is its displacement (Figure)
Weknow ,
`("Circumference") /("arc LENGTH")= (360^(@))/("Angle subtended by are at centre")`
`:. (2pixx(15)/PI)/10=(360^(@))/(20)`
`RARR 2 theta =120^(@)`.`rArr theta 60^(@)`
Now from right angle `Delta ADO`,
`AD=OA sin theta =(15/pi) sin 60^(@)=(15sqrt3)/(2pi)`
`:. AB=2AD=(15sqrt3)/pi cm` along A to B

Note,
Distance is scalar, but displacement is a vector quantiy.
Distance `ge` displacement
If a particle stars from a point and reaches the same point at the end of its journey, then displacement is zero. However distance covered is not zero .
The magnitude of displacement cannot EXCEED the distance of a particle in motion .


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