A particle travels in a circle of radius 20 cm at a uniformly increasing speed. If the speed changes from 8 ms^(-1) to 9 ms^(-1) in 2s, what would be the angular acceleration in "rad s"^(-2) ?

A particle travels in a circle of radius 20 cm at a uniformly increasi

1.	A particle travels in a circle of radius 20 cm at a uniformly increasing speed. If the speed changes from 8 ms^(-1) to 9 ms^(-1) in 2s, what would be the angular acceleration in "rad s"^(-2) ?
Answer» `1.5 "rad s"^(-2)` `2.5 "rad s"^(-2)` `3.5 "rad s"^(-2)` `4.5 "rad s"^(-2)` SOLUTION :Given, radius of the circle `= 20 cm = 20 xx 10^(-2) m` When speed is `8 ms^(-1) and 9 ms^(-1)`, then ANGULAR speeds are respectively `omega_(1)=(8)/(20xx10^(-2))=40 "rads"^(-1)` and `omega_(2)=(9)/(20xx10^(-2))=45 "rads"^(-1)` `:.` Angular acceleration `= (omega_(2)-omega_(1))/(t)=(45-40)/(2)=2.5 "rad s"^(-2)`.