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A particle travels in a circle of radius 20 cm at a uniformly increasing speed. If the speed changes from `8 ms^(-1)` to `9 ms^(-1)` in 2s, what would be the angular acceleration in `"rad s"^(-2)` ?A. `1.5 "rad s"^(-2)`B. `2.5 "rad s"^(-2)`C. `3.5 "rad s"^(-2)`D. `4.5 "rad s"^(-2)` |
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Answer» Correct Answer - B Given, radius of the circle `= 20 cm = 20 xx 10^(-2) m` When speed is `8 ms^(-1) and 9 ms^(-1)`, then angular speeds are respectively `omega_(1)=(8)/(20xx10^(-2))=40 "rads"^(-1)` and `omega_(2)=(9)/(20xx10^(-2))=45 "rads"^(-1)` `:.` Angular acceleration `= (omega_(2)-omega_(1))/(t)=(45-40)/(2)=2.5 "rad s"^(-2)`. |
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