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A particle of mass 1 kg is kept at (1m,1m,1m). The moment of inertia of this particle about Z-axis would beA. `1 "kg-m"^(2)`B. `2 "kg-m"^(2)`C. `3 "kg-m"^(2)`D. None of these |
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Answer» Correct Answer - B Perpendicular distance from Z-axis would be `sqrt((1)^(2)+(1)^(2))=sqrt(2)m` `:. I=Mr^(2)=(1)(sqrt(2))^(2)=2"kg-m"^(2)`. |
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