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A particle traversed half of the distance with a velocity of V_(0).The remaining parts of the distance was covered with velocity V_(1), for half of the time and with V_(2) for other half of the time .Find the mean velocity of the particle averahed and the whole time of motion . |
Answer» Solution : Average VELOCITY for the second half distance `=(v_(1)""t/2+v_(2)""t/2)/(t/2+t/2)=(v_(1)+v_(2))/(2)` Average velocity for the first half distance `=v_(0)` Average velocity for total PATH `=(2v_(0) ((v_(1)+v_(2))/(2)))/(v_(0)+(v_(1)+v_(2))/(2))= (2v_(0) (v_(1)+v_(2)))/(v_(1)+v_(2)+2v_(0))` |
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