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A particle under the action of a force has a period of `3s` and under the action of another force it has a period `4sec` in `SHM`. What will be its period under the combined action of both forces in the same direction?A. `7s`B. `5s`C. `2.4s`D. `0.4s` |
Answer» Correct Answer - C `T = (T_(1)T_(2))/(sqrt(T_(1)^(2)+T_(2)^(2)))` |
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