A particle undergoes a displacement △→r=2.0^i−3.0^j+6.0^k, ending with the position vector →r=3.0^j−4.0^k, in meters, What was its initial position vector?

A particle undergoes a displacement △→r=2.0^i−3.0^j+6.0^k, endin

1.	A particle undergoes a displacement △→r=2.0^i−3.0^j+6.0^k, ending with the position vector →r=3.0^j−4.0^k, in meters, What was its initial position vector?
Answer» A particle undergoes a displacement $△ \to r = 2.0^i - 3.0^j + 6.0^k$ , ending with the position vector $\to r = 3.0^j - 4.0^k$ , in meters, What was its initial position vector?

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A particle undergoes a displacement △→r=2.0^i−3.0^j+6.0^k, ending with the position vector →r=3.0^j−4.0^k, in meters, What was its initial position vector?

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