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A particle undergoes three successive displacements given by `s_(1) =sqrt(2)` m morth - east , `s_(1)=2` m due south and `s_(3) =4 m, 30^(@)` north of west , then mngnitude of net displecement isA. `sqrt(14+4sqrt(3))`B. `sqrt(14-4sqrt(3))`C. `sqrt(4)`D. None of these |
Answer» Correct Answer - B `"we have "S_(1)=(sqrt(2)cos45^(@))hati+(sqrt(2)sin 45^(@)) hatj=hati+hatj` `S_(2)=-2hatjand S_(3)=(-4cos30^(@))hati+(4sin 30^(@)) hatj` `Now ,S=S_(1)+S_(2)+S_(3)=(1-2sqrt(3))hati+hatj` |
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