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A magnitude of vector `vecA,vecB` and `vecC` are respectively `12, 5` and `13` units and `vecA+vecB=vecC` then the angle between `vecA` and `vecB` is |
Answer» Correct Answer - C `|vecA + vecB|=|vecC|` `sqrt(A^(2) + B^(2) + 2AB cos theta)= sqrt(13^(2))` `12^(2) + 5^(2) + 2xx 12 xx 5 cos theta = 13^(2)` `2 xx 12 xx 5 cos theta = 169 - 169 =0` `" "cos theta= 0` `" "theta =(pi)/(2)` |
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