1.

A particle velocity changes from `(2 hati - 3hatj) ms^(-1)` to `(3hati - 2hatj) ms^(-1)` in 2s. If its mass is 1kg, the acceleraton `(ms^(-2))` isA. `-(hati +hatj)`B. `(hati + hatj)//2`C. zeroD. `(hati -hatj)//2`

Answer» Correct Answer - B
`a = (v_(t)-v_(i))/(t) = ((3hati -2hatj)-(+2hatj-3hatj))/(2) = (hati +hatj)/(2)`


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