1.

A particle weighta 120 N on the surface pf the earth . At what height above the earth's surface will its weight be 30 N ? Radius of earth = 6400 km​

Answer»

Answer:

30 =120(1-H/R) => 1/4 = 1-h/R => 1-1/4 = h/R => 3/4 = h/R => h = 3/4(6400) = 4800 km. Height above the earth's surface where the particle WEIGHS 30N = 4800 km. Hope it helps you. Mark me as Brainliest if you THINK I am WORTH of it.



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