A particle, which is constrained to move along the x-axis, is subjected to a force from the origin as `F(x) = -kx + ax^(3)`. Here `k` and a are origin as `F(x) = -kx + ax^(3)`. Here `k` and a are positive constants. For `x=0`, the functional form of the potential energy `U(x)` of particle is.A. B. C. D.

A particle, which is constrained to move along the x-axis, is subjecte

1.	A particle, which is constrained to move along the x-axis, is subjected to a force from the origin as `F(x) = -kx + ax^(3)`. Here `k` and a are origin as `F(x) = -kx + ax^(3)`. Here `k` and a are positive constants. For `x=0`, the functional form of the potential energy `U(x)` of particle is.A. B. C. D.
Answer» Correct Answer - D `F(x)=-kx +ax^(3) ,F_((x)) =0,` for `x = 0 x = sqrt((k)/(a)),` So slope is zero at `x = 0 x = sqrt((k)/(a))`.

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