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A particle who has a constant speed of 50 m/s. it moves along a straight line from A(2,1) to B(9,25). Find its velocity vector. If at initial instant of time it is located at (2, 0), find its final location after 3 s. |
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Answer» SOLUTION :`vec(AB)=vec(B)-vec(A)=7hat(i)+24hat(j)` `vec(v)=(HAT(A)B)|vec(v)|=((7hat(i)+24hat(j)))/(25)xx50 =14hat(i)+48hat(j)` `vec(s)_(2)-vec(s)_(1)(3), and vec(s)_(1)=2hat(i)` `vec(s)_(2)=(42hat(i)+144hat(j))+2hat(i)=(44hat(i)+144hat(j))` |
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