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A particle with charge 2.0 C movess through a uniform magnetic field. At one instant the velocity of the particle is `(2.0hati+4.0hatj+6.0hatk)` m`//`s and the magnetic force on the particle is `(4.0hati-20hatj+12hatk)` N. The x and y components of the magnetic fields are equal. What is `vecB` ? |
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Answer» Correct Answer - `vecB=(-3.0hati-3.0hatj-4.0hatk)T` |
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