1.

A particle with restoring force proportional to displacement and resisting force proportional to velocity is subjected to force Fsinomegat. If the amplitude of the particle is maximum for omega=omega_1 and the energy of the particle is maximum for omega=omega_2, then (where omega_0 natural frequency of oscillation of particle)

Answer»

`omega_1=omega_0` and `omega_2!=omega_0`
`omega_1=omega_0` and `omega_2=omega_0`
`omega_1!=omega_0` and `omega_2=omega_0`
`omega_1!=omega_0` and `omega_2!=omega_0`

Solution :Energy of particle is MAXIMUM at `omega_2=omega_0`
For amplitude RESONANCE (maximum amplitude), frequency of external force
`omega=sqrt(omega_0^2-((b)/(2M))^2)impliesomega_1!=omega_0`


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