A particleisthrownverticallyupwardsitsvelocityat halfof theheightis 10m/sthen themaximumheightattained byit is(g= 10m//s^2)

A particleisthrownverticallyupwardsitsvelocityat halfof theheightis 10

1.	A particleisthrownverticallyupwardsitsvelocityat halfof theheightis 10m/sthen themaximumheightattained byit is(g= 10m//s^2)
Answer» `8 m` `20 m` `10 m` `16m` SOLUTION :fromequationof motion`, v^2= u^2 +2as` ` O= (10)^2+2 2(-10)s ` ` S=5 m` ` u= 10ms^(-1)` ` v=0 ms^(-1)` ` a=- 10 ms^(-2)` totalheight`= 2xx5= 10M`