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A particlele is projected vertically upwards from the ground with a speed V and a speed v and a second particle is projected at the same instant from a height h directly above the first particel with the same speed v at an angle of projection `theta` with the horizontal in upwards direction. The time when the distance between them is minimum isA. `(h)/(2v sin theta)`B. `(h)/(2v cos theta)`C. `(h)/(sqrt2 v)`D. `(h)/(2 v)` |
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Answer» Correct Answer - D In the relative frame `vec(S)_(0)=-hhat(j), vec(u) _(ret) = v cos theta hat(i)+(vsin theta-v)hat(j), vec(a)_(ret) = 0` |
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