A particlemoves form x = 0 to x = 2 m onX - axisunder the effect of a forcevec(F)x = (4x^(3) -3x^(2)+2x) hat(i) newton . The workdone on the particle is

A particlemoves form x = 0 to x = 2 m onX - axisunder the effect of a

1.	A particlemoves form x = 0 to x = 2 m onX - axisunder the effect of a forcevec(F)x = (4x^(3) -3x^(2)+2x) hat(i) newton . The workdone on the particle is
Answer» 22 Joule 36 Joule 46 Joule None of these Solution :Here , force `vec(F) (x) = (4x^(3) -3x^(2)+2x-5) hat(i)N ` is given. Displacementis from 0 to 2m . It is in X - axis . ` :."Work done " W = int_(0)^(2) vec(F) . D vec(x)` ` = int_(0)^(2) (4x^(3) -3x^(2) +2x+5) hat(i) . hat(i) dx ` `= 4[(x^(4))/4]_(0)^(2) -3[(x^(3))/3]_(0)^(2) +2[(x^(2))/2]_(0)^(2)` ` + 5[x]_(0)^(2)` ` ( :. intx^(n)dx = (x^(n+1))/(n+1))` ` = 16 - 8 + 4 + 10 ` ` :. W = 22 J `