1.

A particletiedto a stringof lengthl isdescribinga verticalcircleitsspeedat thebottommostpointis sqrt( 7gl ) .Thenitsspeedat thetopmostpointwillbe

Answer»

` SQRT(gl)`
` sqrt(2GL)`
` sqrt( 3gl)`
`sqrt( 5gl)`

Solution :KINETICENERGYOF theparticleat thebottommostpoint`=(1)/(2) m ( sqrt( 7gl) ^(2))= (7) /(2) gl`
The heightof theparticleis measuredfromthe bottom mostpointand itspotentialenergyat thispointcan bemostpointand itspotentialenergyat thispointcan betakento be`= mg* 0=0 `
` therefore `totalenergyof theparticleat thebottommostpoint
`=(7 )/(2)mg l + 0 =(7)/(2)m gl `
if thevelocityof theparticleat thetopmostpointis v . itskineticenrgy`=(1) /(2)MGL `
ifthevelocityof theparticleat thetopmostpointis ` V ,`itskineticenergy`=(1)/(2)m v^(2)`
andpotentialenergy`= mgh = mg * 2l2mgl`
`therefore ` TOTALENERGY`=((1)/(2) m v^(2) + 2mgl) `
so `(1)/(2) mv^(2)+ 2mgl= (7) /(2)mgl`
or ` (1)/(2)mv^(2)= (3)/(2)mgl ` or`v= sqrt(3gl ) `


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