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A passenger is standing `d` metres away from a bus. The bus begins to move eith constat acceleration `a. To catch the bus the passenger runs at a constant speed (v) towards the bus, What must so that he may catch the bus. |
Answer» Let the passenger catches the bus after time Distance travelled bu the in time (t), ` S_91) =0 + 1/2 at^(2) = 1/2` …(i) Distance travelled by the passenger, (ii) ` S_(2) =v t + 0 v t` The passenger will catch the bus if, ` d+ S_(1) = S_(2)` or ` d + 1/2 at^(2) =v t or 1/2 at^(2) - v t + d =0` or ` t= =([v+- sqrt(v^(2) -2 a d)}])/a` The passenger will catch the bus it 9t) is real, i.e. `v^(2) gt- 2 a d or v gt- sqrt2 ad` Thus minimum speed passenger for catching the bus in ` sqrt 2 ad`. |
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