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A passenger train takes one hour less for a journey of 150 km if its speed is increased by 5 km/hr from the usual speed. Find the usual speed of the train. |
Answer» Time = distance/speed Let the speed of the train be ‘a’ km/hr. Given, passenger train takes one hour less for a journey of 150 km if its speed is increased by 5 km/hr from the usual speed. \(\Rightarrow \frac{150}{a}-\frac{150}{a+5}=1\) ⇒ 150(a + 5 – a) = a2 + 5a ⇒ a2 + 5a – 750 = 0 ⇒ a2 + 30a – 25a – 750 = 0 ⇒ a(a + 30) – 25(a + 30) = 0 ⇒ (a – 25)(a + 30) = 0 ⇒ a = 25 km/hr |
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