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A pendulam of length L and bob of mass M has a speing of force constant K connected a speing of force constsnt K connected horizontally to it at a distance h below is point of suspension. The rod is in equilibrium in vertical podition. The rod of length L. used for vertical suspension s rigid and massless. The frequency of vibration of the system for small values of `theta` is A. `(1)/(2piL)sqrt(gL+(kh)/(m))`B. `(1)/(2piL)sqrt((mgL+k)/(m))`C. `2pisqrt((kL^(2))/(mgL+kh))`D. `(1)/(2piL)sqrt(gL+(kh^(2))/(m))` |
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Answer» Correct Answer - D `T=[mgL sintheta+kh^(2)theta]` For small angle sin `theta ~~ theta` `T=lalpha=-(mgL+kh^(2))theta` `alpha=-(mgL+kh^(2))theta//mL^(2)` `Sof=(1)/(2piL)sqrt(gL+(kh^(2))/(m))` |
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