1.

A pendulum bob is hanging from the roof of an elevator with the help of a light string. When the elevator moves up with uniform acceleration 'a' the tension in the string is T_(1).When the elevator moves down with the same acceleration, the tension in the string is T_(1).If the elevator were stationary, the tension in the string would be

Answer»

`(T_(1)+T_(2))/(2)`
`sqrt(T_(1)+T_(2))`
`(T_(1)T_(2))/(T_(1)+T_(2))`
`(2T_(1)T_(3))/(T_(1)+T_(2))`

Solution :`T_(1)=m(g+a), T_(2)=m(g-a), T=mg`


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