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A pendulum clock that keeps correct time on the earth is taken to the moon. It will run(a) at correct rate (b) 6 times faster(c) √6 times faster (d) √6 times slower. |
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Answer» (d) √6 times slower. EXPLANATION: The time period of the pendulum of the clock on the earth T =2π√(l/g). On the moon g'=g/6. The time period on the moon T' =2π√6l/g) =√6*2π√(l/g) =√6T. So the pendulum will take √6 times more time in one oscillation on the moon and it will run √6 times slower. The option (d) is true. |
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