Saved Bookmarks
| 1. |
A pendulum has time period T for small oscillations. An obstacle P is situated below the point of suspension O at a distance 3l//4 . The pendulum is released from rest. Throughout the motion the moving string makes small angle with vertical. Find the time after which the pendulum returns back to its initial position. |
|
Answer» Solution :After P LENGTH of pendulum becomes `(1)/(4)` Now as `T prop SQRT(L)` , So after P time PERIOD will become `T^(1)= T//2`. Therefore, the DESIRED time will be : `t= (T)/(2)+ (T)/(2)= (T)/(2)+ (T)/(4)= (3T)/(4)` |
|