1.

A pendulum is hung from the rod of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m"/"s^(2) at a distance of 5 m from the mean position. The period of oscillation is...........

Answer»

`1s`
`2pi s`
`2s`
`pi s`

Solution :`|a| = W^(2) x`
`20= W^(2) XX 5`
`therefore W^(2) =(20)/(5)= 4`
`therefore W= 2`
`therefore (2pi)/(T)= 2`
`therefore T= (2pi)/(2)`
`therefore T= pi s`.


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