A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20ms^(-2) at a distance of 5 m from the mean position. To find the time period of oscillation.

A pendulum is hung from the roof of a sufficiently high building and i

1.	A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20ms^(-2) at a distance of 5 m from the mean position. To find the time period of oscillation.
Answer» Solution :`a=20ms^(-2),y=5m""a=OMEGA^(2)y` `20=omega^(2)(5),omega^(2)=4` `omega=2` rad/sec Time PERIOD of oscillation, `T=(2PI)/(omega)=(2pi)/(2)` `T=pisec`