1.

A pendulum is hung in a very high building and is moving freely to and fro like a simple harmonic oscillator. If the acceleration of the bob is 16 ms^(-1) at a distance of 4 m from the mean position, then the time period is

Answer»

2s
1s
`2pis`
`pis`

Solution :Acceleration, `a=16m//s^(2)`
DISPLACEMENT, `y=4m`
According to SHM,
`a=omega^(2)y`
`omega^(2)=(16)/(4)=4`
`THEREFORE omega=2rad//s`
TIME period, `T=(2PI)/(omega)=(2pi)/(2)`
`T=pisec`


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