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A pendulum of length `1 m` hangs from an inclined wall. Suppose that this pendulum is released at an initial angle of `10^(@)` and it bounces off the wall elastically when it reaches an angle of `-5^(@)` as shown in the figure. Take `g = pi^(2) m//s^(2)`. The period of this pendulum is (in second) A. `2//3`B. `3//2`C. `3//4`D. `4//3` |
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Answer» Correct Answer - D We take `theta = (10^(@)) cos (pit)`, calculate t when `theta = -5^(@)`. This gives `t = 2//3 (s)`. The period is 2 times this. |
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