A pendulum of length 60 cm is suspended inside an aeroplane. The aeroplane is flying up with an acceleration of 4m*s^(-2) making an angle of 30^(@) with the horizontal. Find the time period of oscillation of the pendulum.

A pendulum of length 60 cm is suspended inside an aeroplane. The aerop

1.	A pendulum of length 60 cm is suspended inside an aeroplane. The aeroplane is flying up with an acceleration of 4m*s^(-2) making an angle of 30^(@) with the horizontal. Find the time period of oscillation of the pendulum.
Answer» Solution :Horizontal component of ACCELERATION a of the plane = `acos30^(@)` and vertical component = `acos30^(@)` Hence, the downward acceleration experienced by the pendulum BOB = `g-(-asin30^(@))=g+asin30^(@)` So, the acceleration of the pendulum bob `g.=sqrt((g+asin30^(@))^(2)+(acos30^(@))^(2))` `=sqrt((9.8+4xx1/2)^(2)+(4xxsqrt3/2)^(2))=sqrt((11.8)^(2)+12)` `=sqrt(151.24)=12.3m*s^(-2)` `therefore` TIME period of the pendulum `T=2pisqrt(L/(g.))=2xxpisqrt(0.60/12.3)=1.38s`.