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A person adds 1.71 g of sugar `(C_(12)H_(22)O_(11))` in order to sweeten his tea. The number of carbon atoms added are (molecular mass of sugar = 342)A. `3.6 xx 10^(22)`B. `7.2 xx 10^(21)`C. 0.05D. `6.6 xx 10^(22)` |
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Answer» Number of moles of sugar `=(1.71)/(342)=0.005` `because` 1 mole sugar contains `=12xx6.02xx10^(23)` `therefore 0.005` mole of sugar will contain `=12xx0.005xx6.02xx10^(23)` `=0.36xx10^(23)=3.6xx10^(22)` C-atoms |
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