1.

A person adds `1*71` gram of sugar `(C_(12)H_(22)O_(11))` in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar - 342)A. `3*6xx10^(22)`B. `7*2xx10^(21)`C. `0*05`D. `6*6xx10^(22)`

Answer» Correct Answer - A
Moles of sugar added `= (1*71)/(342) = 5xx10^(-3)`
Carbon atoms added
`=12xx5xx10^(-3)xx6*02xx10^(23)`
`= 3.61xx10^(22)`


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