1.

A person fire bullet of 40 g w ith speed of 1200 m /s from his rifle. If rifle can w ithstant maximum recoil force of 144 N. How many bullet he can fire every second ?

Answer»

1
2
3
4

Solution :`F= 144 N`
`m= 40 g= 40 xx10^(-3)kg`
`v=1200 m//s`
Momentumof one buller= mv
Letpersone firen bulleteverysecond
Totalmomentumof nbullet
`=nmv `
RECOIL FORCE
NowF= MNV
`n=(F)/(m v) = (144)/( 40 xx 10^(-3)xx 1200)`
`= 3`
Person can fire3 bulleteverysecond


Discussion

No Comment Found