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A person fire bullet of 40 g w ith speed of 1200 m /s from his rifle. If rifle can w ithstant maximum recoil force of 144 N. How many bullet he can fire every second ? |
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Answer» 1 `m= 40 g= 40 xx10^(-3)kg` `v=1200 m//s` Momentumof one buller= mv Letpersone firen bulleteverysecond Totalmomentumof nbullet `=nmv ` RECOIL FORCE NowF= MNV `n=(F)/(m v) = (144)/( 40 xx 10^(-3)xx 1200)` `= 3` Person can fire3 bulleteverysecond |
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