A person is unable to see objects nearer than 50 cm. He wants to read

1.	A person is unable to see objects nearer than 50 cm. He wants to read a book placed at a distance of 25 cm . Name the defect of vision he is suffering from. How can it be corrected ? Draw ray diagrams for (i) the defective eye ,(ii)its correction using a suitable corrective lens.
Answer» "The person has HYPERMETROPIA DEFECT which is the farsightedness that means that the image formed at BEYOND the retina so it require to be a convergent lens to get focused at retina. The corrective measure is: U = - 25cm v = -50 cm 1/f = 1/v – 1/v 1/f = 1/-50 – 1/-25 1/f = -1 +2/50 1/f = 1/50 P = 1/f = 1/50 = 0.02 cm = 0.0002 D "

A person is unable to see objects nearer than 50 cm. He wants to read a book placed at a distance of 25 cm . Name the defect of vision he is suffering from. How can it be corrected ? Draw ray diagrams for (i) the defective eye ,(ii)its correction using a suitable corrective lens.

Answer»

"The person has HYPERMETROPIA DEFECT which is the farsightedness that means that the image formed at BEYOND the retina so it require to be a convergent lens to get focused at retina.

The corrective measure is:

U = - 25cm

v = -50 cm

1/f = 1/v – 1/v

1/f = 1/-50 – 1/-25

1/f = -1 +2/50

1/f = 1/50

P = 1/f = 1/50 = 0.02 cm = 0.0002 D

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A person is unable to see objects nearer than 50 cm. He wants to read a book placed at a distance of 25 cm . Name the defect of vision he is suffering from. How can it be corrected ? Draw ray diagrams for (i) the defective eye ,(ii)its correction using a suitable corrective lens.

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